Compare two sets of strings and then return whole strings that are different in Python 3.4 -

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I am writing a small API listening program, and I'm trying to figure out that something new has been published. is. I have got more information about this, but I have a problem in the final stage - where I want to print something new. I can compare two lists of objects in the form of set and get the set of characters in the correct answer, but I can not seem to print the actual string.

A list of two lists (both new_revised_stuff and old_revised_stuff strings, like "Bob likes to eat 

 
  / code>  
 returns:  
  set ('b', 'o', 'l' ...)  
 
 I can get rid of 'set' notation by writing: 
 
  list (new_stuff)  
 
 but it does not really help. I like "Bob likes ..." if this is a new line I have also tried: 
 
  new_stuff = [] for a new_revvisest_stuff: B in old_revvisest_stuff: if a! = B: '' .join ( A) New_straf.append (A)  
 
 Which result is in the actual stack overflow, then it is clearly bad code.

< Div class = "post-text" itemprop = "text">

If you want to join any string of single characters in a string, then you do so ''. To join (new_stuff) . For example: 

  & gt; & Gt; & Gt; New_stuff = ['B', 'O', 'L']> gt; & Gt; & Gt; However, there are two problems here, which are built in your design:  
     
  •  The group only holds unique elements. Therefore, if your string is diffs  "hello, bob" , then only  o  and     being set < / Em> 
    •      Therefore, if your string diffs  "likes Bob" , then change it into a set and Then back to a string you get something like  'kioboBls' .  
 
 If any of these problems are (and I suspect that they are), then you have to reconsider your algorithm. You can solve another by using  OrderedSet  ( collections  docs in it), but the first one is going to be more of a problem. / P> 
 So, how can  be?  do you do this? 
 
 OK, you really do not need  new_revised_stuff ; If you iterate over the characters and keep only those people who are not in  old_revised_stuff , as long as  old_revised_stuff  is a set, which can be divided into two sets Any duplicate from a set will end, which I do not think you want is actually a "multiset" in Python, which is similar to 
 
 but  old_revised_stuff  The best way to represent it is usually the  counter .  
 So, I think what you want (probably) is something like this:  
 To snack at http://bobsburgers.com  old_string = '' New_string = 'Bob likes to eat old on http://bobsburgers.com' old_chars = collections.Counter (old_string) new_chars = [] new_string for ch: if old_chars [c]: old_church [ca] - = 1 other: New_upload.append (ca) new_string = '' .join (newmers)

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