Collections module in Python behaves strange? -

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Hi all Python user,

I'm not 100% sure, but it seems that a bug In Python Function collections.Counter () is a part of the archive module. Function collections.Counter () should count the incidents of numbers in a list; in other words, the frequency of the number of vector in this list should be determined. It does not matter whether these numbers are floats or integers in many occasions but this does not work properly, and this is an example when it fails to answer correctly: 

  Import as NPP as import Import Import from import Import imported by import Import plots as matplotlib.pyplot = [250, 250, 251, 251, 251, 251, 251, 251, 251, 251, 252, 252, 252, 252, 253, 253, 253, 253, 254, 254, 254, 254, 254] data_2 = [250, 250, 251, 251, 251, 251, 252, 252, 252, 252, 253, 253, 253, 253, 254 , 254, 254, 254, 254, 255, 256, 256] #s Not allowed for dataDei D3 = D. 2.values ​​() Approved wavelengths d2 = collections.Counter (data_1) in the archive module # for iterations for bears 
    on   
  [2, 4, 4, 4, 5]   using pre> 
 All entries will receive the correct answer (D3). However, if I apply  data_2  to  archive  , then I get the following answer (D 3): 
 
  [2, 2, 4, 4, 4, 5, 1] ​​ 
 
 What is wrong  [2 , 4, 4, 4, 5, 1, 2]  should be read. It looks like  archive. Control ()  exchange some elements, but I do not get any logical explanation, why does it. Btw I am using Python 2.7.5 
 
 What is your opinion on this? 
 
 P.S. 1: Dictionary for the function  dict (in the data for i, data_2 count (i)) i) 2   data_2  for  Gives the same wrong answer for the collection. Control (Data_2)  
 
 PS2:  Resolution  It looks like  by  group >  itertools module  : Importing itertools for group   
 

  group by group group (data2)] The group has a subtype of d3 = [lane (list (group)) = "text"> 
  dict  and does not have a sequence of dictionaries such as, you can call  on the counter object (dictionary!) Outputs using d.values ​​()  are arbitrary and it is unlikely that the incoming What do you want? 
 
 If you want to order values ​​you receive from the key, you should sort the most important values ​​first and then return the value: 
 
  & gt; & Gt; & Gt; Sorted for [V (counter (data_1) .im (), key = lambda x: x [0])] [2, 4, 4, 4, 5]> gt; & Gt; & Gt; [V for Kashmir, in order (counter (data_2) .im (), key = lambda x: x [0])] [2, 4, 4, 4, 5, 1, 2]  < / Ex>

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