regex - python re sub vs findall -

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मेरा कोड: 

  आयात urlib आयात पुनः xml = urllib.urlopen ('url' ) .read ()

मुझे XML टैग से कुछ टैग और उनकी सामग्री को हटाने में दिलचस्पी है, इसलिए, मैं नियमित अभिव्यक्तियों का उपयोग करने की कोशिश करता हूं।

उदाहरण के लिए: < / P> 

  पुनः.फंडॉल (आर 'और एलटी। अंजीर (। *?) & Lt; / fig & gt;', xml, re.DOTALL)

मेल और खाली नहीं है।

हालांकि, 

  re.sub (r '& lt; अंजीर (। *?) & Lt; / fig & gt;', '', xml, पुनः। DOTALL)

कुछ नहीं करता है, XML स्ट्रिंग अपरिवर्तित है। मैं क्यों भ्रमित हूँ, कृपया मदद करें।

का चौथा पैरामीटर नहीं है flags < / कोड>, लेकिन एक की गणना । का मूल्य 16 है (कम से कम पायथन 2.7 / 3.4 में) तो re.sub (.., re.DOTALL) केवल 16 बार बदल देगा।

एक कीवर्ड तर्क के रूप में flags निर्दिष्ट करना आपकी समस्या का समाधान करेगा : 

  re.sub (r '& lt; अंजीर (। *?) & Lt; / fig & gt;', ', xml, flags = re.DOTALL)

उस के अतिरिक्त, re.sub एक प्रतिस्थापन स्ट्रिंग लौटाता है, तीसरे तर्क को जगह में नहीं बदलता है सुनिश्चित करें कि आपने फ़ंक्शन के रिटर्न मान को वापस सौंपा है।


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