python - Is it posible to return on the line with exception? -

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I have a code that looks like this: 

  try: a = Try: Pass [a '] except: [B]: B = form [' B '] except keyError: try the following: c = form [' c '] except keyError: try: D = form [ D] except keyError: pass

is something capable of doing something: 

  try: a = form ['a'] b = form ['b '] C = form [' c '] d = form [' d '] except keyError: some keywords

So if any' a 'form is still working in the form Au Key 'B' and so on

UPD: Sorry, my bad, I do not need to preserve the values, and not one of them. That's why I need a keyword or something that will help me to continue the block even after the exception raises.

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If the form is a dictionary then you can also use syntax Are: 

  & gt; & Gt; & Gt; Form = {'D': 5}> & gt; & Gt; 5)

You can create the function. Format ('a', form.get ('b', form.get ('c', form ['d'])) 5

using some iterators Lazy call: 

 >

edit : if you need all: 

 > gt;> A , B, c, d = map (form.get, ['a', 'b', 'c', 'd']) and gt; & gt; a, b, c, d (none , None, none, 5)

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