Java Character change of a String -

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मेरे पास जावा स्ट्रिंग व्हेरिएबल्स फॉर्मेट हैं (रिक्त स्थान सम्मिलित करें) स्ट्रिंग आईडी = "सीए टी 4443" मुझे अपने स्ट्रिंग मान को id = CA4443 के रूप में टी और रिक्त स्थान को हटाने की आवश्यकता है। 

  मेरे मान सरणी CA T 4443 सीबी टी 4562 सीजी टी 6365 डीए टी 5552 सीएक्स टी 9875 सीएस टी 5454 आरए टी 2377  < / प्री> <पी> दूसरी चुनौती 
 
  सीएएफ टी 444352 सीएबीडी टी 4562 सीजी टी 636535 डीए टी 555255 सीएक्स टी 98755665 सीएस टी 545455 आरए टी 237766   <पी> मुझे इसे प्राप्त करने की आवश्यकता है (केवल 1 2 बार और अंतिम 4 अंक)  
  CA4352 CB4562 CG6535 DA5255 CX5665 CS5455 RA7766

यदि यह हमेशा दो लेटेज़, एक स्थान, एक टी और एक नंबर होता है तो आप ऐसा कर सकते हैं: 

  स्ट्रिंग आईडी = " CA T 4443 "स्ट्रिंग परिणाम = id.substring (0, 2) + id.substring (5, id.length);

या आप बस ऐसा कर सकते हैं: 

  स्ट्रिंग परिणाम = id.replace ("T", "");

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