Using arguments with a PHP script in HTML -

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मैं इस पर एक php स्क्रिप्ट में एक तर्क कैसे पारित कर सकता हूँ: 

  & lt ;? Php '../scripts/listPictures.php' की आवश्यकता होती है; ? & Gt;

अंत में मेरी बहस को जोड़ने से पूरी स्क्रिप्ट को तोड़ने और argv पर vardump का उपयोग करने का कारण बनता है, बस रिक्त देता है।

आप तर्क नहीं भेजते क्योंकि इसमें शामिल / आवश्यकता होती है स्क्रिप्ट चलाता है जैसे कि आपने उस जगह पर लिखा है।

तो बस जांच करें कि स्क्रिप्ट की क्या ज़रूरत है ( एक सत्र में कुछ? अनुरोध पर? शायद एक चर?) और इसे सेट करने से पहले सेट करें।

एक बेहतर तरीका उस सूची में जो कुछ भी होता है उसे चालू करना पिक्चर.एफ़पी एक फ़ंक्शन में है, इसलिए आप वास्तव में भेज सकते हैं मापदंडों

अल्बान का उत्तर बहुत कम के लिए बहुत अधिक है। यह आसान, क्लीनर, तेज़ (दोनों करना है और पीएचपी चलाने के लिए) और कम स्मृति का उपयोग करता है, क्योंकि एक वर्ग बनाना, इसे खोलने, केवल कुछ सरल कार्य = पी के लिए, इसके बजाय मैं इसके अंदर फ़ंक्शन करना चाहता हूं


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