python 2.7 - Open file when path contain folder which name starts with double underscore -

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I can not open a file if its path contains a folder that starts with the name double underscore. For example: 

  file = open ('C: \ user \ __ foldername \ file.txt')

This works if the folder's The name starts only with an underscore, but unfortunately I can not change its name.

Is there a solution?

The reason is not to open the file, because there is no double underscore, that's because an escape character in the string is. Windows paths should be defined using a raw string - from the back side, by avoiding the slash or by using the forward slash, by entering r , 

  file = Open file (r'C: \ user \ __ foldername \ file.txt ') file = open (' C: \\ user \\ __ folder name \\ file.txt ') file = open (' C: / user / __ foldername / file

Something in the path should not be affected by double underscores, it is still a valid path name.


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